Genius.
I would have agreed to this, until I saw equation number 5. Seriously, did your Algebra teacher not teach you Math properly? Whatever you do to one side of the equation, you must also do to the other. You can’t just SQUARE “√problems” and leave “woman” as is! Woman squared ≠ problems. FAILLLLLL.
..okay HAHAHAHA I just released my anger with Math. Fucking subject. It’s ruining my life and it’s foiling my attempts to get into the dean’s list!
Actually, this is manipulation at its finest. you have a point, but you forgot the massive manipulation used by the person here. there’s a statement in #3 which makes everything all right =)
1st: Woman = Money^2
2nd: Money = √problems
3rd: square both sides, Money^2 = √problems^2
which gives us, Money^2 = problems
4th: however, since Woman = Money^2
Therefore, woman = problems.
Proving…yeah right. LOL. it’s magic. haha.
reblogging for the sake of those who messaged me that number 1 equation should be woman = time + money. I tell you guys, the one in the pic is right.
Basically, you can’t add x and y or (x + y) to get 2xy. (wrong!) therefore, time + money = time + money. still don’t get why time and money can’t be added?
Unit for money is, for example, dollar, Unit for time is for example hour or day or week or month. you can’t just simply add two different variables, unless you use equation #2 to satisfy your argument. Nevertheless, equation 1 is right.
Also, let woman = total costs = (time spent) (money spent)
it’s obvious therefore that in order to get/find a woman you need time AND money, which when equated:
y = 2x; letting y = woman, 2 = time, x = money (since more often than not time is an independent variable and money is a dependent variable), which means that the chance you have in finding or getting a woman is directly proportional to the amount of time and money you spend with the girl. Reality. **Unless, the girl you want is easy. Girls that are easy are not much of a problem. (i don’t need to elaborate this mathematically)
To illustrate it in Acctg, it would be:
daily cost in getting or finding woman = (time you spent with the girl) * (money spent per unit of time); assuming this is just for a day. total cost is a different story.
Still not satisfied? then, ill explain further “why AND doesn’t always mean ADDITION.” this is very unnecessary bec the problem is so simple.
First, in order to produce a dress, you need the size of the person AND the materials. You won’t ADD the size of the person and the materials right? perhaps you’ll multiply the size to a material to get how much you need.
Second, to get the distance, you need time AND speed, which makes it d = s x t (Physics)
As for number 4, money is the root of all problems. Just read it this way: speed is distance over time or speed = d/t. therefore, “money is (=) the √(root) of all problems.
See? you don’t always add when you see ‘and.’ Also, you won’t say “to find a woman you need time money” just to make the first equation right. You guys say it like as if you haven’t encountered yet problems like these ones in your whole life. Like as if you always encounter ‘and’ as ‘addition’ only.
Spoon-feeding shouldn’t be practiced. =))
Why did i take this so seriously? well, because i get upset whenever people act as smartypants by attacking something and forgetting to actually extend their LEVEL of thinking. Thinking in steps is very useful. You just don’t do something without thinking of the possible outcomes of the outcomes.
And seriously, this whole thing is supposedly just for fun. i don’t get why people gave such comments.
